Skip to content
🤔prompts chat🧠
🔍
question:How would I sort the list before I return it in getStoredWords?

answer:You can sort the `words` list before returning it in the `getStoredWords()` method by using the `compare()` method. Here's the updated implementation: ```java package ex1; import java.util.ArrayList; import java.util.Arrays; import java.util.Comparator; import java.util.List; public class WordStore { List<String> words = new ArrayList<>(); private static final String[] ORDER = { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten" }; private static final List<String> orderList = Arrays.asList(ORDER); public void add(String numberAsWord) { words.add(numberAsWord); } public List<String> getStoredWords() { words.sort(this::compare); return words; } public int compare(String a, String b) { return Integer.compare(orderList.indexOf(a), orderList.indexOf(b)); } } ``` In the `getStoredWords()` method, the `sort()` method is called on the `words` list by passing the custom comparator `this::compare`. This will ensure that the words are sorted according to the specified order before they are returned.

question:FIx the code so I can use getAllNumbers, at the moment they do not belong to Number class so the code is broke package ex2; import java.util.ArrayList; import java.util.List; public class NumberRepository { private String[] simpleNumberData = "2, 4, 6, 2, 9, 10".split(", "); private String[] scientificNumberData = "2e3, 2e4, 6e3".split(", "); public List<SimpleNumber> getSimpleNumbers() { List<SimpleNumber> simpleNumbers = new ArrayList<>(); for (String simpleNumberDatum : simpleNumberData) { simpleNumbers.add(new SimpleNumber(Integer.parseInt(simpleNumberDatum))); } return simpleNumbers; } public List<ScientificNumber> getScientificNumbers() { List<ScientificNumber> scientificNumbers = new ArrayList<>(); for (String scientificNumberDatum : scientificNumberData) { scientificNumbers.add(new ScientificNumber(Character.getNumericValue(scientificNumberDatum.charAt(0)),Character.getNumericValue(scientificNumberDatum.charAt(2)))); } return scientificNumbers; } public List<Number> getAllNumbers() { List<Number> allNumbers = new ArrayList<>(); allNumbers.add(getSimpleNumbers()); allNumbers.add(getScientificNumbers(); return allNumbers; } }

answer:To fix the code, you need to make `SimpleNumber` and `ScientificNumber` extend the `Number` class. Here's the updated code: ```java package ex2; import java.util.ArrayList; import java.util.List; public class NumberRepository { private String[] simpleNumberData = "2, 4, 6, 2, 9, 10".split(", "); private String[] scientificNumberData = "2e3, 2e4, 6e3".split(", "); public static class SimpleNumber extends Number { private int value; public SimpleNumber(int value) { this.value = value; } @Override public double doubleValue() { return value; } @Override public float floatValue() { return value; } @Override public int intValue() { return value; } @Override public long longValue() { return value; } } public static class ScientificNumber extends Number { private int base; private int exponent; public ScientificNumber(int base, int exponent) { this.base = base; this.exponent = exponent; } @Override public double doubleValue() { return Math.pow(base, exponent); } @Override public float floatValue() { return (float) Math.pow(base, exponent); } @Override public int intValue() { return (int) Math.pow(base, exponent); } @Override public long longValue() { return (long) Math.pow(base, exponent); } } public List<SimpleNumber> getSimpleNumbers() { List<SimpleNumber> simpleNumbers = new ArrayList<>(); for (String simpleNumberDatum : simpleNumberData) { simpleNumbers.add(new SimpleNumber(Integer.parseInt(simpleNumberDatum))); } return simpleNumbers; } public List<ScientificNumber> getScientificNumbers() { List<ScientificNumber> scientificNumbers = new ArrayList<>(); for (String scientificNumberDatum : scientificNumberData) { scientificNumbers.add(new ScientificNumber(Character.getNumericValue(scientificNumberDatum.charAt(0)), Character.getNumericValue(scientificNumberDatum.charAt(2)))); } return scientificNumbers; } public List<Number> getAllNumbers() { List<Number> allNumbers = new ArrayList<>(); allNumbers.addAll(getSimpleNumbers()); allNumbers.addAll(getScientificNumbers()); return allNumbers; } } ``` I've added `SimpleNumber` and `ScientificNumber` as inner classes in `NumberRepository` and made them extend the `Number` class, which requires them to provide an implementation for the following methods: `doubleValue()`, `floatValue()`, `intValue()`, `longValue()`. Finally, I've corrected the `getAllNumbers()` method to use `addAll()` instead of `add()`, since `getSimpleNumbers()` and `getScientificNumbers()` return lists of numbers.

question:Tell me all kind of Service Level agreements partial KPIs and calculation formula in an ITSM team with ITIL version 4, please.

answer:In ITIL version 4, Key Performance Indicators (KPIs) are essential for measuring the success of Service Level Agreements (SLAs) in an IT Service Management (ITSM) team. Here are some common KPIs and their calculation formulas: 1. First Contact Resolution (FCR) rate: Formula: (Number of incidents resolved on the first contact / Total number of incidents) x 100 2. Mean Time to Resolve (MTTR): Formula: Total time spent resolving incidents / Number of resolved incidents 3. Customer Satisfaction (CSAT) score: Formula: (Number of satisfied customers / Total number of surveyed customers) x 100 4. Service Availability: Formula: (Total uptime / (Total uptime + Total downtime)) x 100 5. Incident Response Time: Formula: Total time taken to respond to incidents / Total number of incidents 6. Number of incidents closed within SLA targets: Formula: (Number of incidents closed within SLA target time / Total number of incidents) x 100 7. Number of breached SLAs: Formula: Total number of incidents not resolved within the SLA target time 8. Change Success Rate: Formula: (Number of successful changes / Total number of changes) x 100 9. Problem Resolution Efficiency: Formula: Total number of problems resolved / Total number of problems reported 10. Number of re-opened incidents: Formula: Total number of incidents reopened after being marked as resolved 11. On-time service requests completion rate: Formula: (Number of service requests completed within SLA target time / Total number of service requests) x 100 12. Mean Time to Respond (MTTR) to a service request: Formula: Total time taken to respond to a service request / Total number of service requests Remember that each ITSM team may have additional or different KPIs based on their unique needs and objectives. It's crucial to choose the right KPIs so that your team can pull actionable insights from the data to improve its overall performance and customer experience.

question:Welche Themen aus Fauste der Tragödie erster Teil sind heute noch aktuell.

answer:Einige der Themen aus Goethes Faust - Tragödie erster Teil, die auch heute noch Aktualität haben, sind: 1. Der Kampf zwischen Wissen und Glauben: Der Drang nach Wissen und Fortschritt ist nach wie vor ein wichtiges Thema, insbesondere in einer Zeit, in der Technologie und Wissenschaft eine so große Rolle spielen. Der Glaube hingegen bleibt ein wichtiger Faktor für viele. 2. Der Absturz der Moral: Fausts moralischer Niedergang, der von seiner Sucht nach Vergnügen und seiner Besessenheit von Macht angetrieben wird, ist auch heute noch ein aktuelles Thema, insbesondere in einer Welt, in der Materialismus und persönlicher Gewinn oft wichtiger sind als moralische Werte. 3. Die Rolle der Frau: Die Rolle der Frau in der Gesellschaft und ihre Einschränkungen sind ein allgegenwärtiges Thema, das in der Geschichte von Faust und Gretchen deutlich gemacht wird. 4. Der Zweifel an der Existenz Gottes: Fausts Zweifel an der Existenz Gottes und seine Suche nach einem Sinn des Lebens sind Themen, die auch heute noch relevant sind, insbesondere in einer Gesellschaft, die immer mehr auf Wissenschaft und Fakten ausgerichtet ist. 5. Die Natur als Quelle von Schönheit und Inspiration: Die Natur bleibt auch heute ein wichtiger Aspekt in unserem Leben, und das Bedürfnis, Schönheit und Inspiration in ihr zu finden, ist ein universelles Thema.

Released under the MIT License.

has loaded