answer:Glycerin is typically not taken as a pill to hydrate the body. It is more commonly used as a topical ingredient in lotions, creams, and other skincare or cosmetic products. The reason for this is that glycerin works by attracting and retaining water on the surface of the skin, and it doesn't have the same effect when ingested orally. Drinking enough water and fluids throughout the day is the best way to stay hydrated and maintain healthy skin. If you are experiencing signs of dehydration, it is essential to talk to a healthcare provider about the best ways to treat it.

answer:Glycerol is very similar to glycerin as they both refer to the same compound, which is a colorless, odorless, and sweet-tasting liquid that is commonly used in the health and cosmetic industries. Glycerol is often used in the formulation of dietary supplements that promote hydration, such as sports drinks, as it can help enhance the body's water retention capacity, and thereby aid in rehydration and recovery. Glycerol can also help prevent certain medical conditions such as the development of kidney stones and promote improved exercise performance. However, as with any supplement, it's important to consult with a healthcare professional before taking any glycerol supplements to determine the most appropriate dosage and ensure compatibility with one's medical needs.

answer:#include <iostream> #include <cmath> using namespace std; double S(double x, double eps) { double sum = 1, term = 1, fact = 1; int n = 0; do { term *= 3 * x * x / fact; fact *= (n + 1) * (n + 2); sum += term; n++; } while (abs(term) > eps); return sum; } double Y(double x) { return (1 + 2 * x * x) * exp(x * x); } int main() { double eps, x, h; cout << "Введите точность: "; cin >> eps; cout << "Введите шаг: "; cin >> h; cout << "xtY(x)tS(x)tDelta" << endl; for (x = 0; x <= 1; x += h) { double y = Y(x); double s = S(x, eps); double delta = abs(y - s); cout << x << "t" << y << "t" << s << "t" << delta << endl; } return 0; }

answer:#include <iostream> using namespace std; int main() { int n; double y = 1, term = 1; cout << "Введите n: "; cin >> n; for (int i = 1; i <= n; i++) { term /= 2 * i + 1; y += term; } cout << "y = " << y << endl; return 0; }